2/25 - Where we stand - 1 game left in the regular season

jessej

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Richmond blows out URI and hands GMU a tie with URI for the Conference Championship
we three will finish 1-2-3
1772078577507.png

options
(GMU, URI, Richmond) all win
(GMU, URI, Richmond) all lose

GMU and URI are Co-Champions
URI = #1 Seed
GMU = #2 Seed
Richmond = #3 seed
side note this is the reason i don't like the A-10 unbalanced scheduling - as all teams have not played equivalent schedules
_

GMU wins, URI loses, Richmond wins
GMU is the Champion
GMU = #1 Seed
URI = #2 Seed
Richmond = #3 Seed


GMU loses, URI wins, Richmond loses
URI = Champion
URI = #1 Seed
GMU = #2 Seed
Richmond = #3 seed

GMU loses, URI loses, Richmond wins
3-way tie for Championship

URI = #1 Seed
Richmond= #2 Seed
GMU = #3 Seed

GMU loses, URI wins, Richmond wins
URI = Champion

URI = #1 Seed
Richmond = #2 Seed
GMU = #3 Seed

with a win we are a likely #2 seed, but will need some help to be a #1 seed


1772078281437.png
 
Last edited:

GMUYoda

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Reading the tiebreaker scenarios... I believe Mason is the 3 seed for the A10 tournament if all three teams tie for first at 15-3.

As linked by @psyclone above:

"Three or More-Team Tie

1. Head-to-head competition.

a. Use each team’s record against the tied teams as a group rather than performance
against individual teams. When comparing records against a group of teams, the higher
winning percentage will prevail. In case of tied percentages vs. the team or group of
1.000 or .000, the following shall apply: 2-0 is better than 1-0; 0-1 is better than 0-2.

2. If the above results in two teams remaining, the two-team tiebreaker is used.

3. If more than two teams still remain, use the Conference record of the tied teams based on
winning percentage versus the highest common opponent and proceeding down to the
lowest common opponent, if necessary, until one team gains an advantage."


Mason is 0-1 against URI and 1-1 vs Richmond. URI is 1-1 vs Richmond and 1-0 vs Mason. Richmond is 1-1 vs URI and 1-1 vs Mason.

Mason 1-2
URI 2-1
Richmond 2-2

Mason has the lowest winning percentage, so they get the 3 seed. Richmond would get the 2 seed and URI 1 seed. I believe that would be the correct assessment reading the tie-breaking procedures above.



If GMU and Richmond are tied, Richmond gets the 2 seed and Mason 3 seed. First tiebreaker is head to head which is tied at 1-1. Second tiebreaker looks to be highest common opponent -- which I am assuming would be URI since they would be the 1 seed. RIchmond was 1-1, Mason 0-1... so Richmond gets the 2 seed and Mason 3 seed due to Richmond having the higher winning percentage.


If Mason is ends up the one seed and Richmond and URI are tied -- URI and Richmond head to head are tied 1-1. Highest common opponent used is Mason -- URI is 1-0 and Richmond is 1-1. URI has the higher winning percentage, so URI is 2 seed and Richmond 3 seed.


If I made any errors, please feel free to correct me :)
 

GMUYoda

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Looks like the 2 seed and a10 conference co-champ with URI based off current scores
 
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jessej

jessej

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Davidson #4
Richmond #3
GMU at least #2 as URI is still playing ( and winning)
 

Verdad

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When was their 1st regular season championship? I'm drawing a blank.

I turned on the URI/GW game and saw it was only 12 pts, I blinked and URI up 20 :(
 
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